The Official Homework Help Thread

Hey guys, I really need help with my math homework...it's called Fraction Sequence. It says to identify each point on the line with a fraction. I kind of understand it, but most of the problems are really confusing. Here's a screenshot of ny assignment:

View attachment 148774

This is due by tomorrow, and I need help fast.

well does it give you a formula to follow by? Also do you have a textbook that teaches the lesson?

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Ah i need to go, i will try helping you in a bit. But if its increasing in number than the fraction should also be increasing.
 
@ Dawnpiplup - I'll help you with the second question ^^.

Question 2 asks you to find the numbers that fit in the spaces:

0, _, _, _, 1/3, _, _, _, 2/3

Here's one way to solve the problem with algebra. First notice that there are three numbers in between 0 and 1/3 that are equally spaced apart. Call them a, b, and c so that the sequence begins as 0, a, b, c, 1/3, _, _, _, 2/3. If a, b, and c are equally spaced apart, then the difference between consecutive terms in the sequence are equal. So a - 0 = b - a = c - b = 1/3 - c.

Since a - 0 = b - a, we see that a = b - a, so b = 2a. Similarly, since b - a = c - b we see that c = 2b - a = 2(2a) - a = 3a. So we have three expressions: a = a, b = 2a, and c = 3a. Lastly, we see that 1/3 - c = c - b. So 1/3 = 2c - b = 2(3a) - 2a = 4a. So 1/3 = 4a, and a = 1/12

Since a = 1/12, we see that b = 2/12, and c = 3/12.
 
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@ Dawnpiplup - I'll help you with the second question ^^.

Question 2 asks you to find the numbers that fit in the spaces:

0, _, _, _, 1/3, _, _, _, 2/3

Here's one way to solve the problem with algebra. First notice that there are three numbers in between 0 and 1/3 that are equally spaced apart. Call them a, b, and c so that the sequence begins as 0, a, b, c, 1/3, _, _, _, 2/3. If a, b, and c are equally spaced apart, then the difference between consecutive terms in the sequence are equal. So a - 0 = b - a = c - b = 1/3 - c.

Since a - 0 = b - a, we see that a = b - a, so b = 2a. Similarly, since b - a = c - b we see that c = 2b - a = 2(2a) - a = 3a. So we have three expressions: a = a, b = 2a, and c = 3a. Lastly, we see that 1/3 - c = c - b. So 1/3 = 2c - b = 2(3a) - 2a = 4a. So 1/3 = 4a, and a = 1/12

Since a = 1/12, we see that b = 2/12, and c = 3/12.

I kinda get it now...but if I put 3/12 in the c slot, then next comes 1/3...how much is it increasing by?

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well does it give you a formula to follow by? Also do you have a textbook that teaches the lesson?

- - - Post Merge - - -

Ah i need to go, i will try helping you in a bit. But if its increasing in number than the fraction should also be increasing.


It doesn't give me a formula :( and I didn't look in the book for help, but I got Zandy here helping me XD so I'll just leave it at that...I will look in the textbook now though, I didn't earlier...dumb me. <.<
 
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I kinda get it now...but if I put 3/12 in the c slot, then next comes 1/3...how much is it increasing by?

For question number 2, the solution is:

0, 1/12, 2/12, 3/12, 1/3, 5/12, 6/12, 7/12, 2/3

(The bolded numbers you are given)

Notice that 0 = 0/12, 1/3 = 4/12 and 2/3 = 8/12 though. So the sequence above is the exact same sequence as:

0/12, 1/12, 2/12, 3/12, 4/12, 5/12, 6/12, 7/12, 8/12

From this, you can see that this sequence is increasing by 1/12 each time. You get each successive term of the sequence by adding 1/12 to the previous term ^^.
 
For question number 2, the solution is:

0, 1/12, 2/12, 3/12, 1/3, 5/12, 6/12, 7/12, 2/3

(The bolded numbers you are given)

Notice that 0 = 0/12, 1/3 = 4/12 and 2/3 = 8/12 though. So the sequence above is the exact same sequence as:

0/12, 1/12, 2/12, 3/12, 4/12, 5/12, 6/12, 7/12, 8/12

From this, you can see that this sequence is increasing by 1/12 each time. You get each successive term of the sequence by adding 1/12 to the previous term ^^.

Oh snaps I get it now :D Tysm! :lemon: I'm not just saying this because you gave me the answers to #2 XD btw, I understand. When I was trying to solve it, I didn't realize that 1/3 was also equal to 4/12.
 
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Soooo what do I do when I've turned in the same 2 assignments 3 times and the teacher keeps losing it? I even sent it digitally. I'm pretty sure he's doing it on purpose because I'm gay???
Should I drop the class and pay FAFSA back??
 
Soooo what do I do when I've turned in the same 2 assignments 3 times and the teacher keeps losing it? I even sent it digitally. I'm pretty sure he's doing it on purpose because I'm gay???
Should I drop the class and pay FAFSA back??

Turn them in again. If the teacher really is doing it on purpose you shouldn't give him what he wants.
 
Soooo what do I do when I've turned in the same 2 assignments 3 times and the teacher keeps losing it? I even sent it digitally. I'm pretty sure he's doing it on purpose because I'm gay???
Should I drop the class and pay FAFSA back??

show printed proof that you turned it in at least digitally, if he doesn't "find" it and you suspect it's because of other reasons you should probably make some kind of report to your college dean or something
 
is anyone here good at drawing orthographic views of like objects. currently taking an engineering design class..i dont understand hidden lines at all. im not really interested/good at engineering lmao im only in it coz of STEM
 
is anyone here good at drawing orthographic views of like objects. currently taking an engineering design class..i dont understand hidden lines at all. im not really interested/good at engineering lmao im only in it coz of STEM

lol i hated stem bc i was so bad at it - but my other options for my electives were terrible until i got past my second year of highschool, so i was stuck with stem until then
are you referring to programming the designs or drawing it out on paper?

as you probably already know, hidden lines can only be seen at certain angles. if there's a hidden line 1cm from the side of a square, then on the front/side of it, that specific part of the square is probably higher/lower than everything else. in other words, it stands out and needs to be drawn differently from other angles; just an example. hidden lines are difficult to explain with just words imo, i recommend asking your tech teacher for clarification - but i can put together a quick sketch that shows the concept of hidden lines if you want
 
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lol i hated stem bc i was so bad at it - but my other options for my electives were terrible until i got past my second year of highschool, so i was stuck with stem until then
are you referring to programming the designs or drawing it out on paper?

as you probably already know, hidden lines can only be seen at certain angles. if there's a hidden line 1cm from the side of a square, then on the front/side of it, that specific part of the square is probably higher/lower than everything else. in other words, it stands out and needs to be drawn differently from other angles; just an example. hidden lines are difficult to explain with just words imo, i recommend asking your tech teacher for clarification - but i can put together a quick sketch that shows the concept of hidden lines if you want

Yeah, I knew that much... it's just hard for me to imagine I guess? Idk..I'm sooo bad at sketching and designing and imagining this in general. I'm kind of worried I'll do bad in this class.. I'm no engineer lol. I might ask for help tomorrow regarding the designs :/

Also uh... I think I messed up? I needed to find the equation for a quadratic function that has x intercepts at 1 and 3, but also goes through point (4,8).

1tBYDSe.png


I plugged in the numbers and got 8/9 for the scale factor so i dont think i did it right??

f(x) = a (x-1)(x-3)^2

basically wanted to find a :<
 
Yeah, I knew that much... it's just hard for me to imagine I guess? Idk..I'm sooo bad at sketching and designing and imagining this in general. I'm kind of worried I'll do bad in this class.. I'm no engineer lol. I might ask for help tomorrow regarding the designs :/

Also uh... I think I messed up? I needed to find the equation for a quadratic function that has x intercepts at 1 and 3, but also goes through point (4,8).

1tBYDSe.png


I plugged in the numbers and got 8/9 for the scale factor so i dont think i did it right??

f(x) = a (x-1)(x-3)^2

basically wanted to find a :<
Did you try plugging in x for 4 and f(x) for 8 and then solving for a? I'll try it right now and see what I get.

This is what I did:

f(x)=a(x-1)(x-3)^2
8=a(4-1)(4-3)^2
8=a(3)(1)^2
8=a(3)(1) (remember to do 1 squared first, not 3 times 1 and then square that!)
8=3a
8/3=a

f(x)=(8/3)(x-1)(x-3)^2

Hope this answers your question!
 
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