The Official Homework Help Thread

[KarlaKGB]

To do number three, remember that slope is rise over run, or movement in the Y direction for every movement in the X direction. The slope here is 3/2, which means you move up 3 y coordinates for every 2 x coordinates. The y intercept is -5, so it means that the line intersects the y axis at -5.

i dont see how thats relevant at all, the question just asks for three coordinate solutions to the equation, it's not asking u to draw the line.

u just set x = 0, x = 1 and x = 2, find out the corresponding values of y and list them in the table that's provided

 

[That Zephyr Guy]

i dont see how thats relevant at all, the question just asks for three coordinate solutions to the equation, it's not asking u to draw the line.

u just set x = 0, x = 1 and x = 2, find out the corresponding values of y and list them in the table that's provided

Missed that part, mb. Its still good info to know regardless cus you and I both know she's doing lines next.

 

[DarkDesertFox]

Anyone good at Accounting? I'm having trouble with a couple of transactions.

12th Billed clients for services performed on account, $5,800.

Would you debit Accounts Receivable for $5,800 and credit Service Revenue for $5,800?

17th Received cash payment from client for services performed on this date, $14,000.

I'm thinking you debit Cash by $14,000 and credit Service Revenue by $14,000?

 

[pandapples]

Anyone good at Accounting? I'm having trouble with a couple of transactions.

12th Billed clients for services performed on account, $5,800.

Would you debit Accounts Receivable for $5,800 and credit Service Revenue for $5,800?

17th Received cash payment from client for services performed on this date, $14,000.

I'm thinking you debit Cash by $14,000 and credit Service Revenue by $14,000?

Yep looks good

 

[Jacob]

This may or may not be a little hard to answer / too much to ask for, but I am working on some debate topics for my public speaking class

so if you guys have any information about any of these topics please hmu

1. Why there should be regulations on payday loans
2. Why there should not be regulations on payday loans
3. Why the United States should send $500million to help UN's funding for Syrian Refugees
4. Why the United States should not send $500million to help UN's funding for Syrian Refugees

thanks for your help in advance

 

[EpicGamer12]

Trying to do an a mathematical proof by induction but I can't figure out where I'm going wrong.

For all n in the set of integers, n >= 1, i=1Σn (3i+5) = 1/2(n(3n+13))

I obviously got the base case where both are equal to 8.

For the induction hypothesis, Assume there exists a k in the set of integers, k >= 1 such that i=1Σk (3i+5) =1/2(n(3n+13))

Consider i=1Σk+1 (3i+5) = i=1Σk (3i+5) + i=k+1Σk+1 (3i+5)

for the Σ notation in my post, the prior i initialization represents the bottom and the part on the right represents the top
if you can get this right for me I'll give you 200TBT.

 

[Oblivia]

Trying to do an a mathematical proof by induction but I can't figure out where I'm going wrong.

For all n in the set of integers, n >= 1, i=1Σn (3i+5) = 1/2(2(3n+13))

I obviously got the base case where both are equal to 8.

For the induction hypothesis, Assume there exists a k in the set of integers, k >= 1 such that i=1Σk (3i+5) =1/2(2(3n+13))

Consider i=1Σk+1 (3i+5) = i=1Σk (3i+5) + i=k+1Σk+1 (3i+5)

for the Σ notation in my post, the prior i initialization represents the bottom and the part on the right represents the top
if you can get this right for me I'll give you 200TBT.

Hi.

I think the issue is that these equations aren't equal:

(3i+5) = 1/2(2(3n+13))

If the base case is 8, then I'd expect the right side to be ?(3n+13). Try that and see if it works!

 

[Dawnpiplup]

Ok, so I need help with this math problem. To solve this math problem, you would need to find the area of the shaded area, but I'm a little confused on how to do that. I mean, it gives a hint on how to find the area of the shaded area, and it was this: "Find the total area and subtract the non-shaded area." I still don't really know how to solve it though. Can someone help me on this problem?

Spoiler: Problem #12 on my homework~

 

[That Zephyr Guy]

Ok, so I need help with this math problem. To solve this math problem, you would need to find the area of the shaded area, but I'm a little confused on how to do that. I mean, it gives a hint on how to find the area of the shaded area, and it was this: "Find the total area and subtract the non-shaded area." I still don't really know how to solve it though. Can someone help me on this problem?

Spoiler: Problem #12 on my homework~

View attachment 168911

You can split the entire area into two triangles with bases of 10 and 12 feet, and heights of 16 feet.

With that area, you find the area of the circle and subtract its area from the total area and you have the area of the shaded region.


Post below me is better. I couldn't be bothered to look up the equation for the area of a rhombus lol

 

[Mega_Cabbage]

Ok, so I need help with this math problem. To solve this math problem, you would need to find the area of the shaded area, but I'm a little confused on how to do that. I mean, it gives a hint on how to find the area of the shaded area, and it was this: "Find the total area and subtract the non-shaded area." I still don't really know how to solve it though. Can someone help me on this problem?

Spoiler: Problem #12 on my homework~

View attachment 168911

Area of a rhombus = (diagonal1*diagonal2)/2 = (12*16)/2 = 96
Area of a circle = pi(r)^2 = pi(10/2)^2 = pi(5)^2 = 78.54

96-78.54 = 17.46 = shaded area

At least I think that's right. It's hard to look at it sideways.

 

[Mimi Cheems]

I swear to god polynomials, monomials, trinomials, and binomials will be the death of me. I had a hard time seeing what was up on the board in Algebra earlier today, and I didn't understand how the degree is supposed to be determined... Like I get that the degree for the monomial of 5 is 0 since there are no x's in the monomial, but what would the degree be for a polynomial like this; 5x^8 + 3x^3 + 2x^4? Wouldn't the degree be 15 since that's how many x's are in the polynomial?

 

[aericell]

I swear to god polynomials, monomials, trinomials, and binomials will be the death of me. I had a hard time seeing what was up on the board in Algebra earlier today, and I didn't understand how the degree is supposed to be determined... Like I get that the degree for the monomial of 5 is 0 since there are no x's in the monomial, but what would the degree be for a polynomial like this; 5x^8 + 3x^3 + 2x^4? Wouldn't the degree be 15 since that's how many x's are in the polynomial?

The degree of the polynomial is the highest degree of the terms. It's not the total number of x's in the polynomial, you don't add them up. So in something like 6x^9 + 4x^5 + 2x^3, the degree would be 9 since it's the highest degree of x.

I hope that made sense and you can apply it to your problem

 

[Blu Rose]

NEVERMIND FIGURED IT OUT I'M EXTREMELY STUPID FOR NOT REALISING THE SIMPLICITY

Spoiler: don't open my thought process makes me cry

Spoiler: haha

i'm too lazy to pull up how the teacher did this, it involves getting out ipad and i'm on spring break so screw it
it's probably really simple and i just don't want to think it through
it's fairly obvious to begin that the equation on the right is another way to express something of the form cos (x + y)
i also want to say that the dividing by h is probably just something to make it look complicated af and we can probably just multiply that and get that out of the way
if cos h - 1 = sin h so help me god

EDIT:
is confirmed that cos h - 1 does not equal sin h (logically)
but this introduces that the whole right part isn't actually some way to represent cos (x + y)...? after all, if
cos h - 1 does not equal sin h then that means what i typed in the previous sentence
i'll just sleep on it and figure it out in the morning or smh

or maybe i'm taking an entirely different look and because f(x) is apparently equal to cos x, i need to do something about that and simplify it for it to make sense
then that makes f(x + h) = cos x + h? which then makes the entire left part 1
1 = cos x ((cos h - 1) / h) - sin x (sin h / h)
ok sorry i'm way off now i bet lol

 

[N e s s]

bump this back up, people could use some help.

Also can someone explain Direct objects in spanish for me?

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bump this back up, people could use some help.

Also can someone explain Direct objects in spanish for me?

 

[skarmoury]

I don't know anything about Spanish, sorry :c
And is anyone here good with Chemistry? I have two problems regarding acid-base titrations I can't seem to figure out D:

 

[ams]

I don't know anything about Spanish, sorry :c
And is anyone here good with Chemistry? I have two problems regarding acid-base titrations I can't seem to figure out D:

I used to be a chemistry tutor for a number of years so feel free to pm me if you still need help

 

[Kanaa]

hhglh i need help with this math problem:

In June 2016, there are 20 raccoons. Every 3 months, the raccoon population doubles. At what point will the island have 1730 raccoons?

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also;; apparently the answer is between 19-20 years

 

[pipty]

hhglh i need help with this math problem:

In June 2016, there are 20 raccoons. Every 3 months, the raccoon population doubles. At what point will the island have 1730 raccoons?

- - - Post Merge - - -

also;; apparently the answer is between 19-20 years

I think the answer should be between 19-20 months instead of years. Try using the doubing-time formula

 

[KarlaKGB]

also got 19.3 months

20 * 2^n = 1730
n = 6.435 (how many times the population doubles before it reaches 1730)
so months = 6.435 * 3 = 19.3 cuz the population doubles every 3 months

 

[visibleghost]

old thread but heeeyyy help me out pls

basically, someone was selling tickets because money am i right. they sold 2000 tickets.
x tickets sold for 800 kr each
y tickets sold for 550 kr each
1 539 500 kr in total was earned

so ik that the answer is y=242 and x=1758 but how tf do i do that without guessing..............,