The Official Homework Help Thread
- Thread starter Zandy
- Start date
how 2 make these rotated parabolas connect
Is it necessary to outline the head with piecewise connected parabolas? It might be simpler to use an ellipse xP.
well
after 20 mins i got it
i tried rotating an ellipse but it wasnt close enough to the head shape sadly
A^3 + B^3 = C^3
I need to find some combination of A, B, and C that will make this equation work out. A, B and C have to be integers greater than 0. If anyone can help me solve this, I'll give them all my bells and half my cakes.
I need to find some combination of A, B, and C that will make this equation work out. A, B and C have to be integers greater than 0. If anyone can help me solve this, I'll give them all my bells and half my cakes.
Mega_Cabbage
Meh
You can't solve it. Check Fermat's last theorem.
https://en.m.wikipedia.org/wiki/Fermat's_Last_Theorem
You may want to look up Fermat's Last Theorem.
Thanks but I don't think my teacher would appreciate it if he asked me to solve for A, B, and C, but instead I gave him a wikipedia article. I can just imagine that I'd be the laughingstock of my whole class.
Unfortunately, like Oblivia and Mega_Cabbage have said, there are no nontrivial integer solutions to A^3 + B^3 = C^3 though. A proof can be found here though it's rather lengthy and complicated.
If n is a positive integer then nontrivial solutions to A^n + B^n = C^n exist only in the cases when n=1 and n=2.
