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7th? o__O....
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Simplify different bases? What exactly does your worksheet say?
7th? o__O....
Its made up of 12 problems, one example is z/z^5
I mean, what is it telling you to do. It has instructions right?
wouldnt that be z^-4?Its made up of 12 problems, one example is z/z^5
Its made up of 12 problems, one example is z/z^5
wouldnt that be z^-4?
I just watched a few videos, it seems that the person who said subtracting the exponenets was right. I think I can figure it out on my own now.
^= TO the power ofThey worksheet told me that I need to simplify with different bases...
wouldnt that be z^-4?
That is correct. z/z^(5) would equal(=) z^(1) - z^(5) which would equal(=) z^(-4)
z/z^(5) is not the same thing as z^(1) - z^(5). I know what you meant, but just to prevent confusion.
z/z[SUp]5[/SUp] = z[sup]1 - 5[/sup] = z[sup]-4[/sup] OR 1/z[sup]4[/sup]
z/z^(5) is not the same thing as z^(1) - z^(5). I know what you meant, but just to prevent confusion.
z/z[SUp]5[/SUp] = z[sup]1 - 5[/sup] = z[sup]-4[/sup] OR 1/z[sup]4[/sup]
1/z^4 is inverting, which is z^-4. It's the same thing. 1/z^4 = z^-4
1/ 2^(4) = 1/16 which = 2^(-4) which = 1/16
Also what do I o with that extra number? Such as
6ng^3 x (2n^2 x g^3)
*The six and the first two
You add them together + the variable I think
Like j?(j⁴)= J⁸