You always switch. The chances of you getting it right the first time is 1/3. But your chances increase to 1/2 when one of the answers is revealed. This is an example of the Monty Hall problem
You always switch. The chances of you getting it right the first time is 1/3. But your chances increase to 1/2 when one of the answers is revealed. This is an example of the Monty Hall problem
You chances actually increase to 2/3, but the rest is correct. Plus points for even getting the name of the problem! So you win a banana and..... the mystery prize. *dun-dun-dunn*
Thanks to everyone who participated! I didn't expect everyone to answer so quickly, haha. I'm still in the process of contacting the winners and waiting for the prizes to be claimed, so to everyone who won, please sit tight!
1. You have three cousins: Chief, Wolfgang, and Lobo. One day, you ask Lobo, "How old are the three of you?" He answers, "Well, the product of our ages is 490. The sum of our ages is 26." Feeling confused, you ask him for more clues. "Well...I'm the oldest of us three, and my age is twice that of Chief," Lobo says.
How old is Wolfgang? SOLVED BY MAYORKIYO Prize: New Year's Noodles, ceramic hotpot, stewpot
The product of their ages is 490, which is also equal to 7 * 7 * 5 * 2. There are only a few possible ways we can arrange these four factors into three different numbers:
1) 49, 5, 2 (product is 490, sum is 56)
2) 35, 7, 2 (product is 490, sum is 44)
3) 14, 7, 5 (product is 490, sum is 26)
4) 10, 7, 7 (product is 490, sum is 24)
Now the only combination which fits the criteria (sum = 26) is combination (3). The question is, which of these three numbers represent Wolfgang's age? Lobo is the oldest of the three, so it must mean that he's 14 years old. His age is twice that of Chief, and so Chief is 7 years old. The remaining number, 5, is Wolfgang's age.
2. An unknown number of tourists wish to go on a trip. They decide to rent an equally unknown number of buses, each of which has a maximum capacity of 10 passengers. What we do know, is that, if all of the buses take on 8 passengers, one tourist will be left without a ride. And if the tourists try to fill up all the buses to maximum capacity, they will fill up all but one bus, which will have only one passenger.
How many buses and tourists are there? SOLVED BY DACOSIM Prize: 1 million bells
It's probably easier if we write this problem as a series of simple math equations. Let B be the number of buses, and T the number of tourists.
"If all buses take on 8 passengers, one tourist will be left without a ride" can be expressed as:
8*B = T - 1
And "they will fill up all but one bus, which will have only one passenger" can be written as:
10*(B - 1) + 1 = T
Solving the two equations together, we get B = 5, and T = 41.
3. You have $2, $5, $10 and $20 bills. Without knowing which you're getting, you place your hands in your pocket and grab two of the bills at the same time.
How many possible combinations of two bills let you buy a $12 chocolate bar? SOLVED BY RANDOMSHEEP101 Prize: Afternoon tea set plus a cup of coffee
The only possible combination of two bills you could have that has a sum less than $12 is $5 and $2 taken together. All you would need to do is to figure out how many possible combinations you can have from the bills and subtract 1.
You can be all math-y about it and compute the number of combinations by using the formula 4!/(2!2!), giving you 6, or you can just list down all the combinations you can think of, also giving you 6.
6 minus 1 gives 5, which is the right answer.
4. Pietro and Julian went cherry-picking one day. "Hey, if you only picked 17 more cherries, then you would have picked twice the number of cherries I have right now, glitter," said Julian. "That's funny," Pietro replied. "If you picked 17 more cherries, then you'd have twice my number of cherries too!"
How many cherries have the two of them picked? SOLVED BY DOLBY Prize: Leaf bed, sprout table, sunrise lamp, and a cherry-blossom clock
Once more, it might be better to solve this by expressing it as math equations, but it's also quite simple enough to be immediately solved just by figuring things out.
The only way that both of them will need the same amount of additional cherries is when they have an equal number of cherries! And since they need 17 more to double that number, then that must also mean they each have 17 cherries at hand. 17 times two is 34, which is the answer we need.
5. Vesta, Wendy, Eunice and Muffy just went on holiday. In addition, they brought along either a paper parasol, a lacy parsol, a mint umbrella, or a leaf umbrella. You know the following details:
- The villager with the mint umbrella did not go to the city, nor did she go to the island.
- Wendy went to the mountains.
- The villager who went to the city used a lacy parasol.
- Eunice decided to take a trip to the lake.
- Vesta uses a paper parasol.
Where did each of them go, and what umbrella did they bring? SOLVED BY LADY LOKI Prize: Golden watering can, plus 2 blue roses
I messed this puzzle up a bit by letting it have two possible solutions instead of just one. ^^; Either one of them is a valid answer.
We know that Eunice went to the lake, Wendy went to the mountains, and that Vesta used a paper parasol. That means that Muffy must have been the one to go to the city and use a lacy parasol, because that's the only combination that still remains.
The remaining destinations are island, mountain (Wendy) and lake (Eunice). Therefore, Vesta must have gone to the island with the paper parasol.
Either Wendy or Eunice could have used the mint umbrella. That leaves the other villager with a leaf umbrella.
6. The diabolical Tom Nook has trapped you in a 4ft by 5ft room and flipped a switch to fill it with water. He fills it with 100 cubic feet of water before dashing off to escape.
What should your minimum height be so that your head will be just above the water line? SOLVED BY PAWPAW Prize: Hair-bow wig
4 times 5 gives you 20 square feet, which is the total area of the room. If you divide the volume of water, 100 cubic feet, by that figure, it will give you the height of the water. The answer is 5 ft, plus of course the height of your head!
7. You are a contestant in an exciting game show where there are three doors, two of which contain a bag of coal, and one containing a shiny diamond, the grand prize. You pick a door, at random, at the beginning of the show. The host, wishing to make the game more exciting, opens one of the two remaining doors to reveal a bag of coal. He then gives you a choice: stick with your original choice of door, or change your tune and go with the last unopened door instead.
Assuming you want to win the diamond, should you or should you not stick with your first choice -- and why? SOLVED BY VODKASMIZMAR Prize: A banana, and a 7-11 ABD
This is a minor variation of a puzzle known as the Monty Hall Problem. If you search around the intertubes, you'll find a lot of explanation and discussion about it.
When you picked your first choice, the probability that that door will hold the diamond is 1/3 (since it's one out of three doors). The probability that the other doors, regardless of how many unopened doors there actually are, will have the diamond is therefore 2/3.
Our kind host has reduced the number of doors to just 2. You're stuck with the 1/3 probability, while you know that the other door is twice as probable (1/3 * 2) to have the winning prize. Should you switch? Yes!
Thank you again for everyone who answered! I didn't expect people to solve it so quickly, so I'm still really pleasantly surprised. This was my first giveaway, and you made it an absolute blast. c: